Electronics Engineer $137$ is $(2n+1)^3+3n^2$ for $n=2$ The simplest rearrangements of the cancelling harmonic series converge to the logarithms of positive rationals. $$ logleft(frac{p}{q}right)=sum_{i=0}^infty left(sum_{j=pi+1}^{p(i+1)}frac{1}{j}-sum_{k=qi+1}^{q(i+1)}frac{1}{k}right) $$ $pi^2$ is so close to $10$ because $$sum_{k=0}^inftyfrac{1}{((k+1)(k+2))^3}$$ is small. ©